[Calculus] Chain Rule
$$ \frac{d g[f(x)]}{d x} \bigg|_{x = a} = \frac{d g(y)}{d y} \bigg|_{y = f(x)} \cdot \frac{d f(x)}{d x} \bigg|_{x = a} $$
Last Updated on 2023/08/16 by A1go
$$ \frac{d g[f(x)]}{d x} \bigg|_{x = a} = \frac{d g(y)}{d y} \bigg|_{y = f(x)} \cdot \frac{d f(x)}{d x} \bigg|_{x = a} $$
Last Updated on 2023/08/16 by A1go